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Jharkhand Staff Selection Commission (JSSC) has published the latest job notification for the 4919 Constable Vacancies. Candidates who are qualified in 10th must grab the chance of the JSSC Recruitment 2023. Eligible and Interested Candidates can apply online from 15th January 2024 to 14th February 2024. Check more details like eligibility criteria such as educational qualification, consolidated remuneration, age limit, selection process, application fee, how to apply, and important dates mentioned below.
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Vacancy Details & Educational Qualification:
| Name of the Post | Number of Vacancies | Educational Qualification |
| Constable | 4919 | 10th |
Age Limit:
- The applicant's age should be 18 to 25 years.
Selection Process:
- The Selection Process will be based on the Physical Efficiency Test/Physical Measurement Test/Medical Examination/Interview.
Pay Scale:
- Candidates will get a remuneration of Rs.21,700/- to Rs.69,100/-per month.
Application Fee:
- For Other Candidates: Rs.100/-
- For SC/ST Candidates: Rs.50/-
How to Apply for the JSSC Jobs 2023:
- Visit the Official Website of the JSSC.
- Verify the Notification details.
- Click on the Apply Online Link.
- Registration, Log in with your Email ID and Password.
- Fill out the complete details in the application form.
- Upload the scanned copies of the Documents.
- Pay the application fee.
- And, Submit the Online application form.
Important Dates:
| Opening date to Apply Online | 15th Jan 2024 |
| Closing date to Apply Online | 14th Feb 2024 |
| Official Notification | Click Here |
| Apply Online Link | Click Here |
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